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Pai: 1 5 =5 2 5 =25 3 5 =125 4 5 =625 3 => ?=5 respectiv 125 Alecu Ioana Andreea, scoala cu clasele I-VIII Smeeni, Buzau
Seria reprezinta puterile lui 5, deci lipseste puterea a III-a a lui 5, adica nr. 125. Solutie: 1,5,25,125,625.
125
am spus localitatea logicus mai sus unde gresisem
1x5=5 5x5=25 --*25x5=125*--- 125x5=625 RASPUNS:125 putinei andreea-irina galati
sunt o fata foarte desteapta la scoala in clasa a3ac
mia placut foarte mult
Au raspuns corect: Ionut Ghinea, Ploiesti si Nica Mihaela Catalina (fara localitate ?)
upsss am gresit deci 1x5=5 5x5=25 5x25=125 5x125=625 asta este logica sirului
RASPUNDE LOGICUS TE ROG
Seria reprezinta puterile lui 5, deci lipseste puterea a III-a a lui 5, adica nr. 125. Solutie: 1,5,25,125,625. Ionut Ghinea, Ploiesti
Deci avem 1;5;25;?;625.Eun cred ca semnul intrebarii este 25 deoarece 1x5=5 5x5=25 si 25x25=625 Nica Mihaela Catalina jud.prahova loc.ploiesti str.domnisori nr.81 bloc.62 sc A ap. 2 scoala i.a.bassarabescu cls a IV-a B
